Doubt from capacitor


I stucked while writing charge as function of time. Help anyone.

384?

Yes..

Find work done by battery(W=qV) and change in potential of capacitor.Heat loss=W-( change in U)


I have its soln
Could you pls tell from where 3/2 came.

Initially, charge was CE/2 in 1st capacitor and finally both capacitor has 2CE charge therefore total charge flown from battery is 3CE/2

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Thanks bro.
I got it.
I make silly mistake by considering the first capacitor to be fully charged initially.

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