It's like joining two capacitors in series, (1,2) And (3,4)
Nah.. that's fine..i want to know at which surface and how much charge gets distributed .. how to get?
Ok..but how ? Didn't get it..
And for this question 77..
Marked equipotenial points and find equivalent resistance between Capacitor,
thanks bro.. got it @pratyaksh_tyagi
Nvm got it
It's D Na
How is (a) possible here in question 53 ?
Is the answer for (I) 6V?