Doubt from capacitance

Question no 16 i am getting answer as 16micro coloumb but not in options

Ans will be 18\mu C

Please tell the working after calculation of current in circuit i think i did a mistake in my calculation.

Current is 1.5A so that branch(which has capacitor)has a potential difference (12-3)=9V
Charge =9×2=18

I was getting current 11 A as i had taken all three resistance in series. Then how did you calculate current ?

No 3 but 2 resistance
At steady state there will be no current through
4 Ohm