# Doubt from binomial theorem

Yes and for question 10 is n(n+1)^2/12 but i got something wrong i got n(n+1)(9n^2-5n+2)/12

Wait a minute I send the solutions

1 Like

For 10 I got
\displaystyle \frac{n(n-2)(n+1)^2}{12}

But is written (n+2) maybe answer key is wrong.

Actually now I got
\displaystyle \frac{n(n+2)(n+1)^2}{12}
@abhijit_2020

1 Like

In last step it should be \displaystyle n(n+1)^2 \frac{6n+6+3n-8n-4}{12}

I also got i found out where i made mistake.

How to find coefficient of x^r in (1-x)^-n here power is negative how to find it ? I want to solve one question from jan shift 2019 i am stuck here.

Question 17 couldn't understand the solution given in this book.