# Doubt from atomic structure

For

N=1 -> l=1 -> m= -1,0,1

N=2 -> l=0,2 -> m= 0 ; -2,-1,0,1,2

N=3 -> l=1,3 -> m= -1,0,1 ; -3,-2,-1,0,1,2,3

N=4 -> l=0,2,4 -> m= 0 ; -2,-1,0,1,2 ; -4,-3,-2,-1,0,1,2,3,4

For each M there are 2 electrons

6,12,20,30

I'm getting (3) instead of (4). Where am I going wrong?

**Aniket_1**#4

Here 0 is also there so it might happen that n=0,2,4,6,... Are odds and n=1,3,5,7.. are even , try with that i will try on paper asap

**Akash_1**#5

No, the approach is not wrong however the question asks for Electron number of n=1,2,3,4 and not number of electrons in each n=1,2,3,4.

Thus, the question needs to be approached this way