B is only possible when after acylation there is rediction
How? Can u show mech?
Or some reliable source?
70 B is correct tertbutyl carbocation is very stable so CO gets removed
But why acylation is not happening?
how is CO getting removed as CO is not much stable too
Why CO is not stable? infact tertbutyl cation formed with CO are much stable than before thus tertbutyl carbocation will attack.
I think cuz atmosphere mai CO2 jada hota hai in comparison to CO aur CO ke compounds sunne mai bhi ni aate
Btw in all rxns with tertiary carbocation forming by removal of any group will happen?
At higher temperatures formation of CO is more favourable than CO2 you can look at Ellingham Diagram.
Idk I have encountered only this one case yet so im not sure.
Try other ques
Edit:It's incorrect.I just checked my copy and breaking like this take place because of hinderence not because of stability.
Can u check ques 65 I have doubt in b option
In my opinion B should be incorrect what's the answer given?
Its given correct i think too it should be incorrect as formation of cpm occurs
After reading this answer
Kota teachers be like - I'm I a joke to you?
Don't know if the above information is true or not
The one who answered doesn’t seem legit look at his profile
Tho I found this one abit outside the JEE sphere
Found this in my notes
Aye smoke what you doing here?