Yeah I thought the same.
What do you think?
147 is d only, check answer key correctly bro
H attached to carbon next to aldehyde group i.e \alpha\,Carbon is more acidic as @Ronit_Mandal said
In my PDF it's given c
Thanks for cross check
That is higly unlikely. I think I have the same pdf and there answer is d only
Send me the pic of answer key @Chirag_Hegde
Oh sorry , it's given D but according to me it should be c
Phenol ke sath conjugation is more stable than resonance with O right?
Maybe, which is more acidic m not sure. Your reasoning seems right though.. More conjugation is there.
There might be some concept here i don't know. Others will help
Oh okay, thanks tho.
Can you tag the ones who are good at this?
Edited the reply
@Anish_Saparia @Viraam_Rao @Satyendra_Srivastva see q 147 post#6
Answer is D
K_2CO_3 \rightarrow2K^+ +CO_3^-
CO_3^- will attack α-H then simultaneously the Br will go out from adjacent position .
@Udit_Takkar That will yield d
H from carbon adjacent to carbonyl i.e C2 and then Br from the carbon adjacent to that carbon i.e C1
The question is H at which carbon is more acidic, C1 or C2
C2 I think
C2 imo too.
I also think C2
I have seen in some questions even hoffman becomes major product even if its not that stable due to steric reason
What steric hinderance here both carbon has same space to attack @Udit_Takkar
H on C2 should be more acidic as
K2Co3 is bulky base,
Both carbon will provide almost equal hindrance
C1 has benzene with it