Does it help if you write the phenyl rings as Ph in the diagram?
Like that way it doesn't look so intimidating..
I just blindly removed alpha H. Formed the double bond but then I am stuck. I don't see how there are isomers?
I think you don’t have to do the condensation.
There’s no heat, right? Just the aldol
Like see after I remove alpha hydrogen I get carbanion. Then I made that carbanion into a double bond and the ketone into an OH.
Why do catechol and all those give positive tests?
You did intramolecular?
OMG, I might sound crazy but doesn't the compound remind you of favourskii?
No no forget this. idk what I did at first.
Isn’t favorskii limited to alpha halo aldehydes/ketones?
No halogen here
@Chirag_Hegde their tautomers are carbonyl compounds
Ohh right. What else do we do here?
Did you understand what I did at first?
Hydroquinone ka samjha lekin catechol and resorcinol ka kaisa hoga oxidised structure?
I think its like HCOOH also gives this test(its not oxidizing)
No, could you post your steps?
I was trying to take two molecules of that whole thing and then aldol it. That’s why it became so intimidating.
OHH WAIT AGAIN TAUTOMERISE!!
Yeah, I understand that. But mechanism kya hoga? Same as intramolecular aldol?
You’ll get back the reactant if you do that @Viraam_Rao
Is the answer 4
hahahaha. THAT WAS HILARIOUS.
No idea. Please show ur steps.
But now the second carbon atom doesn't have fixed configuration like the reactant.
I mean after tautomerisation, we would get both reactant and some other form of reactant. Right?
Yeah, that’s right
There's an equilibrium between it's tautomers
And there are 2 tautomers possible
And once it forms a tautomers and regains the keto form there are two ways in which it can do so
(The configuration of ph ph or ph H can change)
So 2*2 4
Can you draw and show?
Like this ?
@Viraam_Rao how did you know we have to do this? Why not usual aldol with 2 reactant molecules??
Yeah that's exactly what I meant