Not getting last step
Can you explain the last step indetail. Not clear
The un hindered =0 is oxidized to acid and other one is reduced to alcohol now acid attacks and alcohol leaves
The doubt is how it cyclises
After acid donation it is heated
So O- of alcohol will attack acidic carbon and OH from acid removes
Acid derivates show SNae rxns and not acid it self. So O can't attack C of -COOH
That's how Easter formation occurs
Ester formation occurs in baaic medium. SNae on acid cannot occur in acidic medium. As acids tend to form anion in acidic medium
@Shantanu_Thakur pleaSe see this
@chetan_pandey Do you have solomons fryle? This is carbocation capture by carbonyl. Page 739 bottom part.
PS: Adapted edition.
Can you send the photo?
Sorry for the inverted image.