Water is a stronger acid so reactant is reformed
Could you elaborate?
Reaction between naoh and ethanol is an acid base reaction, so ethanol acts as an acid, and water is formed as the product. But as water is a stronger acid than ehanol, the equilibrium is far towards left so water dissociates to form Ethanol again
He was asking 32 @Chirag_Hegde
Thanks but I asked Q32
My guess would be,
During formation of ketone we get more % of elimination product than during formation of aldehyde.
But aldehyde oxidises to acids but secondary alcohol only to alcohol
I'm not sure, let's wait for someone else's opinion.
@Mayank_Agarwal u sure ans is correct ?because a tiny amount aldehyde may oxidise to acid
Could it be steric hinderance, that 2ALC is more bulky than 1ALC therefore reacts slowly and yields less product.
Yes in book it's given that
Please someone confirm from coaching institute archives