I think 1,4
For first one we need strong bases like NH2-
For 4 th one though the - charge will be stabilised.........but due to steric hindrance na oh won’t abstract H.
I feel 3 and 4 but my tukka goes to 4
I think steric repulsion has no effect here as OH- is small molecule.
It will only 1.
1 and 4 is correct..
Naoh is not a strong base??
Compared to nanh2 it is not strong base .
Also the H in sp carbon is not very highly acidic ..so to remove it we need strong base.