@Churchil_Dwivedi @Abhijeet_Singh @Sushant_Kumar_Mishra @Mayank_Dixit sir plzz reply.
Gauche>eclipsed>anti I guess.
But anti >eclipsed.Here we cant consider H bonding!
Mm yeah, sorry.
No!Gaushe>anti>eclipsed according to me!
No no. In gauche, there will be repulsive interaction between OH and F brother. Three bulky lone pairs on F and two on OH.
No bro @ananda_krishnan you are forgetting steric hinderance when OH and F are near thus decreasing stability of eclipsed.
But it is learned under a special case that H bonding dominates that repulsive effect!!
But Hydrogen Bonding will occur if it was simply an alcohol. Here the halogen substituent will cause great repulsion.
Gauche should be more stable than anti here…
Guys gaushe is more stable.I found it out inOPT.
@Sarmila thnx.Yur correct!
Yes this is due to hydrogen bonding.
For example if u will replace OH with NH_2 then also due to H bonding , gauche will be more stable than anti.
Not only that -cooh,-cooR etc also have same reason!
How can we say that the F atom will interact with Her only?? It can interact with O also??
@Churchil_Dwivedi ek baar eyes close KAR ke poore Mann se Hbonding ke structure ko yaad karo answer khud mil jayega
@Churchil_Dwivedi Thats how H bonding is!!
It wont interact with O as stability is not achieved