Hey! Many students are having doubt in this question. Go through que A8 of this thread, you will understand.
Sir I am not understanding configuration of h^- ion but I know the concept of degeneracy
See, H^- ion is called hydride
We know that single H contains 1 electron and one proton
But H^- ion contains two electron and one proton.
Because of -ve sign on H, the electron is gained.
Thus the configuration is 1s^2 due to presence of 2 electrons.
Sir I understood this now .Sir now what about configuration of h^- ion about 1 exited state .Is first excited state is n,=2 for hydride ion ?
First excited state will be
Sir can you explain one again of h^- ion for this question
What you want to ask?
Please ask specifically.
Sir I understood the concept of degeneracy but I am not understanding that how electon in h^- ion goes to 2s from 1s and from 2s to 2p and why we are leaving for 2s orbital with no electrons .sir can you please explain all about configuration of h^- ion
Excitation always takes place when energy is absorbed.
Therefore when some bonds are formed, excitation of electrons takes place to make binding pair with electrons of other atoms.
Sir not understood clearly
What will happen when electron jumps from px orbital to py orbital.Is there electromagnetic radiation released or not.
See, have you learnt Molecular Orbital Theory?
This states that px,py and pz have different energy levels. Thus if electron jumps from state of lower energy to higher energy, then obviously electromagnetic radiation will release.