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Center of Mass, Momemtum, Collision
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Center of Mass of semi circular wire

B) Center of Mass of semi circular wire:

Derivation:

Total length of semi circular wire = R

Elemental length = Rdq

So

C) Center of Mass of a uniform semi circular plate:

Derivation:

Here the element chosen is a thin wire (semi circular) of radius r.

As derived earlier, the for this is at .

Dumb Question:

1)      Why is here?

Ans: The mass dm is a semi circular thin wire whose position is variable (y is not unique), so we concentrate dm mass on the COM of this wire that is at .

D) Center of Mass of hemispherical shell:

Derivation:

Dumb Question:

1)      Why is y = Rsinq here?

Ans: The Center of Mass of elemental ring is at its center (by symmetry) which is at a height of Rsinq from origin; hence y = Rsinq.

E) Center of Mass of a hemisphere:

Derivation:

Dumb Question:

1)      Why is volume of elemental disc = Rdq (cosq) (pR2cos2q) and not

Rdq (pR2cos2q)?

Ans: This is a solid hemisphere. If we consider the curvature at the ends of the disc as negligible (as we do in a hollow shell as in the previous case) then the integration starts yielding wrong results. So as a tip we can take this that whenever the integration is being done over solid objects, the curvature effects cannot be neglected!

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